Answer: We have to solve the sinusoidal equation on the Interval [0,2pi):
[tex]-8\cos (x)=3[/tex]
Simplifying gives:
[tex]\cos (x)=-\frac{3}{8}\Rightarrow(1)[/tex]
Taking the functional Inverse gives:
[tex]x=\cos ^{-1}(-\frac{3}{8})[/tex]
The answer is:
[tex]x\approx1.955r\Rightarrow\lbrack0,2\pi)[/tex]
