Let x be the length of the longest piece in inches, then we can set the following equation:
[tex]x+(x-\frac{164}{6})=\frac{345}{8}[/tex]Solving for x we get:
[tex]\begin{gathered} 2x=\frac{345}{8}+\frac{164}{6}=\frac{1035+656}{24}=\frac{1691}{24} \\ x=\frac{1691}{48}\approx70.46 \end{gathered}[/tex]Therefore the length of the longer piece is 70.46in,