Question

What is the Triangle G at 273 k for the following process at 1.0 atm?

Answer 1

The ΔG is 5.61 kJ.

To calculate the ΔG of a chemical reaction, it is necessary to use the formula of ΔG, and replace the values:

$\begin{gathered} \Delta G=\Delta H-T\cdot\Delta S \\ \Delta G=31.0\frac{kJ}{\text{mol}}-273K\cdot0.093\frac{kJ}{\text{mol}} \\ \Delta G=5.61kJ \end{gathered}$

Remember to convert 93.0 J to kJ to solve it.

So, the ΔG for this reaction is 5.61 kJ.