Question

Find the Area of the figure below, composed of a rectangle and onesemicircle, with another semicircle removed. Round to the nearesttenths place.

Answer 1

Area of semicircle is:

$A_{sc}=\frac{\pi r^2}{2}$

Area of rectangle is:

$A_r=\text{length }\times\text{ width}$

Length = 13

Width = 12

Diameter of circle =12

$\begin{gathered} \text{Radius}=\frac{d}{2} \\ =\frac{12}{2} \\ =6 \end{gathered}$

Area of shape is:

$\text{Area}=\text{ rectangle area+semicircle area-othe semicircle area}$$\begin{gathered} \text{Area}=(\text{length}\times\text{ width)+}(\frac{\pi r^2}{2})-(\frac{\pi r^2}{2}) \\ =(13\times12)+(\frac{\pi(6)}{2}^2)-(\frac{\pi(6)^2}{2}) \\ =13\times12 \\ =156 \end{gathered}$

Area of shape is 156.