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the prime factors of 40 and 56 are

[tex]\begin{gathered} 40=2,5 \\ 56=2,7 \end{gathered}[/tex]

we can write out the factors of 40 and 56 i.e number that will divide both 40 and 56 without remainder

[tex]\begin{gathered} 40=1,2,4,5,8,10,20 \\ 56=1,2,4,7,8,14,28 \end{gathered}[/tex]

the common factors are 1, 2 , 4 and 8 and the highest amongst them will give us the GCF and which is 8

the answer to the question is 8

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