we know that
Any right triangle, must satisfy the Pythagorean Theorem
c^2=a^2+b^2
where
c is the hypotenuse (the greater side)
a and b are the legs of righ triangle
In this problem we have
a=1
b=1
Find the value of c
[tex]\begin{gathered} c^2=1^2\text{ +1\textasciicircum{}2} \\ c^2=2 \\ c=\sqrt[]{2} \\ c=1.4 \end{gathered}[/tex]therefore
the answer is