Question

solve for b3/4b + 9 = 21

Answer 1

$\frac{3}{4b}+9=21$

subtract 9 from both-side

$\frac{3}{4b}=21-9$$\frac{3}{4b}=12$

cross multiply

$48b=3$

Divide both-side by 48

$b=\frac{3}{48}$$b=\frac{1}{16}$