Question

What is the decay constant for Pollonium-212 if the half-life is 299x10^-9 s?

Answer 1

The radioactive half-life is given by:

$T_{1/2}=\frac{ln(2)}{\lambda}$

Where:

$\begin{gathered} T_{1/2}=299\times10^{-9}s \\ so: \\ \lambda=\frac{ln(2)}{299\times10^{-9}} \\ \lambda=2.32\times10^6s \end{gathered}$