Solution:
Given the equation:
[tex]y=x+6\text{ ----- equation 1}[/tex]
When x=-6, substitute the value of -6 for x in equation 1.
Thus,
[tex]\begin{gathered} y=x+6 \\ \text{where x=-6} \\ y=-6+6 \\ \Rightarrow y=0 \end{gathered}[/tex]
When x=0, substitute the value of 0 for x in equation 1.
Thus,
[tex]\begin{gathered} y=x+6 \\ \text{where x=0} \\ \text{thus,} \\ y=0+6 \\ \Rightarrow y=6 \end{gathered}[/tex]
When x=1, substitute the value of 1 for x in equation 1.
Thus,
[tex]\begin{gathered} y=x+6 \\ \text{where x=1} \\ \text{thus,} \\ y=1+6 \\ \Rightarrow y=7 \end{gathered}[/tex]
Hence, we have the following paired solutions:
[tex]\begin{gathered} (-6,0), \\ (0,6), \\ (1,7) \end{gathered}[/tex]
Using the above paired points, the graph of the equation
[tex]y=x+6[/tex]
is as shown below:
