Question

Answer the questions below about the quadratic function. f(x) = 2x ^ 2 - 20x + 49

Answer 1

$f(x)=2x^2-20x+49$

Since the leading term has a positive coefficient, the function is concave up and has a minimum value.

The minimum value of the quadractic function is given by:

$-\frac{b^2-4ac}{4a}=-\frac{(-20)^2-4\cdot2\cdot49}{4\cdot2}=-1$

This minimum value occur at:

$-\frac{b}{2a}=-\frac{(-20)}{2\cdot2}=5$