Question

solve by factorization 48n^2 -3n^4=0

Answer 1

Given:-

$48n^2-3n^4=0$

To find the value by factorization.

So now we simplify,

$\begin{gathered} 48n^2-3n^4=0 \\ 3n^2(16-n^2)=0 \\ 3n^2=0,16-n^2=0 \\ n=0,n^2=16 \\ n=0,n=14 \end{gathered}$

So the values are 0 and 14.