Question

a group fitness classifies it's fitness class attendees by class type and member status the marketing team has gathered data from a random month In which there were 2065 class attendees (see uploaded picture)

Answer 1

Given the data of the table, we must find the probability that a class attendee:

• A = is a non-member of the gym and is attending a barre class,

,

• or B = is a member of the gym and is attending a yoga class.

The total probability is the sum of the probabilities of each event:

$P=P(A)+P(B)\text{.}$

The probability of event A is given by:

$P(A)=\frac{\#\text{non}-\text{members that goes to barre class}}{\#\text{total attendes }}=\frac{282}{2065}\cong0.1366.$

The probability of event B is given by:

$P(A)=\frac{\#\text{members that goes to yoga class}}{\#\text{total attendes }}=\frac{209}{2065}\cong0.1012.$

So the total probability is:

$P\cong0.1366+0.1012=0.2378.$

Answer

The probability is 0.2378.