Question

Which is an equivalent form of the following function?g(x)= (1-x^2)divided by x^2a) g(x)=1 divided by x^2 - 1 divided by xb) g(x) (1 divided by x^2 ) - xc) g(x)= (1/x^2) - 1d) g(x) = 1/x^2

Answer 1

The given function is

$g(x)=\frac{1-x^2}{x^2}$

It can be written as follows.

$\text{ Use }\frac{a+b}{c}=\frac{a}{c}+\frac{b}{c}\text{.}$

$g(x)=\frac{1^{}}{x^2}-\frac{x^2}{x^2}$

$g(x)=\frac{1^{}}{x^2}-1$

Hence option c is correct.