The roots of a qaudartic equation,
[tex]ax^2+bx+c=0[/tex]
is,
[tex]x=\frac{-b\pm\sqrt[]{(b)^2-4ac}}{2a}[/tex]
The value of a, b and c for the given equation is,
a = 2
b = 7, and
c = -3.
Determine the roots of the quadratic equation.
[tex]\begin{gathered} x=\frac{-7\pm\sqrt[]{(7)^2-4\cdot2\cdot(-3)}}{2\cdot2} \\ =\frac{-7\pm\sqrt[]{49+24}}{4} \\ =\frac{-7\pm\sqrt[]{73}}{4} \end{gathered}[/tex]
So option A is correct answer.
