Here, we want to get the expected pay off value of having a ticket
To do this, we will have to work with probability
From the question;
one will win $140
11 will win $120
12 will win $90
The rest will win nothing
The number of tickets that will win nothing is;
200-(1+11+12) = 176
The probability of having a ticket that will win $140 is; 1/200
The probability of having a ticket that will win $120 is 11/200
The probability of having a ticket that will win $90 is 12/200
Now, let us calculate the expected value of winning;
We have that as;
[tex]\begin{gathered} (\frac{1}{200}\times140)\text{ + (}\frac{11}{200}\times120)\text{ + (}\frac{12}{200}\times90) \\ \\ =\text{ 0.7 + 6.6 + 5.4 = 12.7} \end{gathered}[/tex]Furthermore, we need the expected value of losing, and with that, we can arrive at the expected payoff