Solution
Step 1:
Given data:
Her house is at (−4, 9).
Her school is at (−4, 3).
The community center is at (1, 3).
The grocery store is at (−4, −8).
Part A
Her house is at (−4, 9).
Her school is at (−4, 3).
[tex]\begin{gathered} Distance\text{ = }\sqrt{(x_2-x_1)^2+(y_2-y_1)^2} \\ \\ =\sqrt{(-4-(-4))^2+(3\text{ - 9\rparen}^2} \\ \\ =\text{ }\sqrt{0^2\text{ +\lparen-6\rparen}^2} \\ \\ =\text{ }\sqrt{36} \\ =\text{ 6 units} \end{gathered}[/tex]Maria's house to her school is 6 units
Part B
The total distance from Maria's house to the school to the grocery store
= 6 + 11
= 17
The total distance from Maria's house to the school to the community center
= 6 + 6
= 12
YES
The total distance from Maria's house to the school to the grocery store is greater than the total distance from Maria's house to the school to the community center