Given that the tuition T for one year is represented by the equation below
[tex]T=\frac{1}{8}x+9[/tex]Where x is the year since 2000, and T is in thousands of dollars
Statement of Problem: To find tuition for a year in 2020.
In other to find the tuition, we would first find x
Step 1: Find x
[tex]\begin{gathered} x=2020-2000 \\ x=20 \end{gathered}[/tex]After getting x to be 20, we would then substitute for x in the equation for the tuition
Step 2: Substitute for x
[tex]\begin{gathered} T=\frac{1}{8}x+9 \\ T=\frac{1}{8}\times20+9 \\ T=2.5+9 \\ T=11.5 \end{gathered}[/tex]After getting T, let us find the value of T in thousands of dollars
Step 3: Find T in thousands of dollars
[tex]\begin{gathered} T=11.5\times\text{ \$1000} \\ T=\text{ \$11,500} \end{gathered}[/tex]Hence, the tuition T for one year at this college in 2020 is $11,500