Respuesta :

Solution

The two foci are (+ae, 0), and (-ae, 0)

[tex]\begin{gathered} e=\sqrt{1+\frac{b^2}{a^2}} \\ \\ a=6,b=8 \\ \\ \Rightarrow e=\sqrt{1+\frac{64}{36}}=\frac{5}{3} \end{gathered}[/tex][tex]ae=6\times\frac{5}{3}=10[/tex]

The answer is

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