We must find the other endpoint of a line with:
• midpoint M = (4, 8),
,• first endpoint EP1 = (9, -10).
The parts of the line are given in the following graph:
So we see that the second endpoint is given by:
[tex]EP2=M-U.[/tex]The vector U is given by:
[tex]U=EP1-M=(9,-10)-(4,8)=(9-4,-10-8)=(5,-18).[/tex]Using this in the equation of the second endpoint, we get:
[tex]EP2=(4,8)-(5,-18)=(4-5,8-(-18))=(-1,26).[/tex]AnswerThe coordinates of the missing endpoint are (-1, 26).