Consider the following functions,S(x) = -15 - x and g(x) = 4 - *Step 2 of 2: Find the domain of (8 - D«). Express your answer in interval notationAnswerDomain in interval notation:

Given the functions:
[tex]\begin{gathered} f(x)=-\sqrt{5-x} \\ \\ and \\ \\ g(x)=4-x \end{gathered}[/tex]Let's find the domain of (g - f)(x) in interval notation.
To solve for (g - f)(x), let's solve for g(x) - f(x).
Subtract f(x) from g(x).
We have:
[tex]\begin{gathered} (g-f)(x)=g(x)-f(x)=(4-x)-(-\sqrt{5-x}) \\ \\ (g-f)(x)=(4-x)-(-\sqrt{5-x}) \end{gathered}[/tex]Solving further:
Apply distributive property and remove the parentheses.
[tex](g-f)(x)=4-x+\sqrt{5-x}[/tex]Now, let's find the domain.
The domain is the set of possible values of x which makes the function defined.
To find the domain set the values in the radicand greater or equal to zero and solve for x.
[tex]\begin{gathered} 5-x\ge0 \\ \\ \text{ Subtract 5 from both sides:} \\ -5+5-x\ge0-5 \\ \\ -x\ge-5 \\ \end{gathered}[/tex]Divide both sides by -1:
[tex]\begin{gathered} \frac{-x}{-1}\ge\frac{-5}{-1} \\ \\ x\leq5 \end{gathered}[/tex]Therefore, the domain is:
x ≤ 5
In interval notation, the domain is:
[tex](-\infty,5][/tex]ANSWER:
[tex](-\infty,5][/tex]