The given fraction expression :
[tex]\frac{3}{8}+\frac{1}{8}[/tex]Since, from the property of fraction,
If the denominator of the set of fractions which are adding are equal then the numerator are sum up:
[tex]\frac{a}{b}+\frac{d}{b}+\frac{x}{b}=\frac{a+d+x}{b}[/tex]Since in the given expression the denominator ie equal to 8
thus, numerator will add
[tex]\begin{gathered} \frac{3}{8}+\frac{1}{8}=\frac{3+1}{8} \\ \frac{3}{8}+\frac{1}{8}=\frac{4}{8} \\ \text{ Since, 4 divided 8 by 2} \\ \frac{4}{8}=\frac{1}{2} \\ \frac{3}{8}+\frac{1}{8}=\frac{1}{2} \end{gathered}[/tex]Answer : 1/2