Let's solve the following equation
[tex]\frac{2x}{8}-\frac{3x}{4}=\frac{1}{2}[/tex]First, we find the least common factor between the denominators.
8 4 | 2
4 2 | 2
2 1 | 2
1
So, the least common factor would be the product 2x2x2 = 8.
Now, we use the least common factor to subtract the fractions, where the new denominator is 8.
[tex]\frac{2x-6x}{8}=\frac{1}{2}[/tex]Then, we solve for x
[tex]\begin{gathered} -\frac{4x}{8}=\frac{1}{2} \\ -4x=\frac{1}{2}\cdot8 \\ -4x=4 \\ x=\frac{4}{-4} \\ x=-1 \end{gathered}[/tex]