Question

A. Translate the verbal phrases into algebraic expressions.1. 13 times b plus 22. 27 multiplied to w divided by 33. The square of the quotient of 54 and j4. K divided by the square root of 65. Q to the 10th power subtracted from 100

Answer 1

Explanation

So first of all we have "13 times b plus 2". 13 times b is given by just taking the variable and multiplying it by 13:

$13\cdot b=13b$

Then we add 2 to this expression so we get:

$13b+2$

At item 2 we have "27 multiplied to w divided by 3". We first multiply 27 and w:

$27\cdot w=27w$

Then we divide this expression by 3:

$\frac{27w}{3}$

In item 3 we have "The square of the quotient of 54 and j". We first write the quotient of 54 and j:

$(\frac{54}{j})$

Then we square it:

$(\frac{54}{j})^2$

At 4. we have "K divided by the square root of 6". The square root of 6 is:

$\sqrt{6}$

Then we take K and we divide it by this root:

$\frac{K}{\sqrt{6}}$

Finally, we must translate "Q to the 10th power subtracted from 100​". Q to the 10th power is:

$Q^{10}$

Then we take 100 and we substract the last expression:

$100-Q^{10}$Answer

Then the answers are:

$\begin{gathered} 1.\text{ }13b+2 \\ 2.\text{ }\frac{27w}{3} \\ 3.\text{ }(\frac{54}{j})^2 \\ 4.\text{ }\frac{K}{\sqrt{6}} \\ 5.\text{ }100-Q^{10} \end{gathered}$