Solve for the Surface Area of the triangular pyramid. The base is an equilateral triangle.Surface Area =

Answer:
44 square mm
Explanation:
The surface area of the triangular pyramid is the sum of the surface areas of the 4 triangles.
Since the base is an equilateral triangle, the surface area:
[tex]S.A.=\text{Area of Base Triangle+3(Area of One side)}[/tex]Base Area
[tex]A=\frac{1}{2}bh=\frac{1}{2}\times4\times1=2\operatorname{mm}^2[/tex]Area of one side
[tex]A=\frac{1}{2}bh=\frac{1}{2}\times4\times7=14\operatorname{mm}^2[/tex]Thus, the surface area is:
[tex]\begin{gathered} S\mathrm{}A\mathrm{}=2+3(14) \\ =2+42 \\ =44\operatorname{mm}^2 \end{gathered}[/tex]The surface area is 44 square mm.