Respuesta :

Answer:

44 square mm

Explanation:

The surface area of the triangular pyramid is the sum of the surface areas of the 4 triangles.

Since the base is an equilateral triangle, the surface area:

[tex]S.A.=\text{Area of Base Triangle+3(Area of One side)}[/tex]

Base Area

[tex]A=\frac{1}{2}bh=\frac{1}{2}\times4\times1=2\operatorname{mm}^2[/tex]

Area of one side

[tex]A=\frac{1}{2}bh=\frac{1}{2}\times4\times7=14\operatorname{mm}^2[/tex]

Thus, the surface area is:

[tex]\begin{gathered} S\mathrm{}A\mathrm{}=2+3(14) \\ =2+42 \\ =44\operatorname{mm}^2 \end{gathered}[/tex]

The surface area is 44 square mm.

ACCESS MORE
EDU ACCESS
Universidad de Mexico