The equations of three lines are given below.Line 1: y=5/2x-7Line 2: 10x-4y = -2Line 3: 2y = 5x+7For each pair of lines, determine whether they are parallel, perpendicular, or neither.

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We have the following set of equations,

[tex]\begin{gathered} y=\frac{5}{2}x-7 \\ 10x-4y=-2 \\ 2y=5x+7 \end{gathered}[/tex]

To know whether they are parallel or perpendicular we need to have all three equations in slope-intercept form, or

[tex]y=mx+b[/tex]

Line 1,

[tex]y=\frac{5}{2}x-7[/tex]

Line 2,

[tex]\begin{gathered} 10x-4y=-2 \\ -4y=-2-10x \\ y=-\frac{10x}{-4}-\frac{2}{-4} \\ y=\frac{5}{2}x+\frac{1}{2} \end{gathered}[/tex]

Line 3,

[tex]\begin{gathered} 2y=5x+7 \\ y=\frac{5}{2}x+\frac{7}{2} \end{gathered}[/tex]

Notice, all three lines have a slope of m = 5/2

Since the slopes are all the same, all three lines are parallel

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