Solution
Note: Law of Indices
[tex]\begin{gathered} a^m\times a^n=a^{m+n} \\ and \\ a^0=1 \end{gathered}[/tex]To solve the problem
[tex]\begin{gathered} a^2\times a^{-3}\times a=a^2\times a^{-3}\times a^1 \\ a^2\times a^{-3}\times a=a^{2-3+1} \\ a^2\times a^{-3}\times a=a^0 \\ a^2\times a^{-3}\times a=1 \end{gathered}[/tex]Therefore, the answer is
[tex]1[/tex]