Respuesta :

ANSWER

[tex]x=3[/tex]

EXPLANATION

We want to find the axis of symmetry of the parabola given:

[tex]y=-x^2+6x-8[/tex]

The general form of the equation of a parabola is:

[tex]y=ax^2+bx+c[/tex]

The axis of symmetry is given as:

[tex]x=-\frac{b}{2a}[/tex]

From the given equation:

[tex]a=-1;b=6[/tex]

Therefore, the equation of the axis of symmetry is:

[tex]\begin{gathered} x=-\frac{6}{2(-1)} \\ x=-\frac{6}{-2}=-(-3) \\ x=3 \end{gathered}[/tex]

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