ANSWER
[tex]x=3[/tex]EXPLANATION
We want to find the axis of symmetry of the parabola given:
[tex]y=-x^2+6x-8[/tex]The general form of the equation of a parabola is:
[tex]y=ax^2+bx+c[/tex]The axis of symmetry is given as:
[tex]x=-\frac{b}{2a}[/tex]From the given equation:
[tex]a=-1;b=6[/tex]Therefore, the equation of the axis of symmetry is:
[tex]\begin{gathered} x=-\frac{6}{2(-1)} \\ x=-\frac{6}{-2}=-(-3) \\ x=3 \end{gathered}[/tex]