For any right triangle
We have that:
[tex]a^2+b^2=c^2[/tex]This is called the Pythagorean Theorem.
Now, let's use this theorem to find which sets could be the side lenghts of a right triangle:
[tex]\begin{gathered} 8\operatorname{cm},15\operatorname{cm},17\operatorname{cm} \\ 8^2+15^2=17^2\rightarrow289=289\text{ }✅ \\ \\ 3\operatorname{cm},5\operatorname{cm},6\operatorname{cm} \\ 3^2+5^2=6^2\rightarrow34\ne36\text{ }❌ \\ \\ 5\operatorname{cm},12\operatorname{cm},14\operatorname{cm} \\ 5^2+12^2=14^2\rightarrow169\ne196\text{ }❌ \\ \\ 1.2\operatorname{cm},2.4\operatorname{cm},2.6\operatorname{cm} \\ 1.2^2+2.4^2=2.6^2\rightarrow7.2\ne6.76\text{ }❌ \end{gathered}[/tex]This way, the correct answer is: Option A