Question

Use Right Triangle Trigonometry to solve this problem. Round your answer to the nearest TENTH.

Answer 1

50 ft from the tower

angle=60°

since we know the angle and the Adj leg

we want to solve the Opp leg

then

$tan(\theta)=\frac{Opp}{Adj}$$tan(60)=\frac{Opp}{60}$$60tan(60)=Opp$$60\sqrt{3}=Opp$$Opp=103.92304$

Rounded to the nearest tenth

the tower is 103.9 ft tall