Explanation
[tex]\begin{gathered} x(x+3)=10 \\ x^2+3x-10=0 \\ (x+5)(x-2)=0 \end{gathered}[/tex]
The above equation has two solutions. x = -5 and x = 2.
However, since the original equation is in terms of logarithms we only take the positive solution which would be x = 2.
