Find the time required for an investment of 5000 dollars to grow to 8500 dollars at an interest rate of 7.5 percent per year, compounded quarterly

Find the time required for an investment of 5000 dollars to grow to 8500 dollars at an interest rate of 75 percent per year compounded quarterly class=

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Solution:

Given:

[tex]\begin{gathered} Pr\text{ incipal, P=\$5000} \\ \text{Amount, A=\$8500} \\ \text{Rate, r=7.5\%=}\frac{7.5}{100}=0.075 \\ \text{Number of compounding (quarterly), n =4} \\ t=\text{?} \end{gathered}[/tex]

The formula for finding the amount in compound interest is given by;

[tex]A=P(1+\frac{r}{n})^{nt}[/tex]

Substituting the values to get the time it will take,

[tex]\begin{gathered} A=P(1+\frac{r}{n})^{nt} \\ 8500=5000(1+\frac{0.075}{4})^{4t} \\ \frac{8500}{5000}=(1+0.01875)^{4t} \\ 1.7=1.01875^{4t} \\ \text{Taking the logarithm of both side to get t,} \end{gathered}[/tex][tex]\begin{gathered} 1.7=1.01875^{4t} \\ \log 1.7=\log 1.01875^{4t} \\ \text{Applying the law of logarithm below;} \\ \log a^x=x\log a \\ \text{Then,} \\ \log 1.7=4t\log 1.01875 \\ \text{Dividing both sides by log1.01875} \\ \frac{\log 1.7}{\log 1.01875}=4t \\ \frac{0.2304}{0.008068}=4t \\ 28.557=4t \\ \text{Dividing both sides by 4 to get the value of t,} \\ t=\frac{28.557}{4} \\ t=7.13925 \\ t\approx7.14years \end{gathered}[/tex]

Therefore, the time is approximately 7.14years.

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