Answer
a₉ = 13122
Explanation
The nth term of a geometric progression is given as
[tex]a_n=a(r^{n-1})[/tex]
where
a = a₁ = first term = 2
r = common ratio = 3
We are then asked find the 9th term of this sequence
n = 9
[tex]\begin{gathered} a_n=a(r^{n-1}) \\ a_9=2(3^{9-1}) \\ a_9=2(3^8) \\ a_9=2(6561) \\ a_9=13122 \end{gathered}[/tex]
Hope this Helps!!!
