The equation:
[tex]x^2+7x-2=0[/tex]
has the values a=1, b=7 and c=-2; hence the discriminant is:
[tex]7^2-4(1)(-2)=49+8=57[/tex]
Since the disciminant is positive this means that the equation will have two different solutions.
The solutions can be found using the general formula:
[tex]\begin{gathered} x=\frac{-7\pm\sqrt[]{7^2-4(1)(-2)}}{2(1)} \\ x=\frac{-7\pm\sqrt[]{57}}{2} \end{gathered}[/tex]
therefore the solutions are:
[tex]\begin{gathered} x=-\frac{7}{2}+\frac{\sqrt[]{57}}{2} \\ \text{and} \\ x=-\frac{7}{2}-\frac{\sqrt[]{57}}{2} \end{gathered}[/tex]