Given the following System of Equations:
[tex]\begin{cases}9x-4y=11 \\ x+4y=19\end{cases}[/tex]You can solve it using the Elimination Method:
1. Since the y-terms are:
[tex]\begin{gathered} -4y \\ 4y \end{gathered}[/tex]You can add the equations:
[tex]\begin{gathered} \begin{cases}9x-4y=11 \\ x+4y=19\end{cases} \\ --------- \\ 10x+0=30 \\ 10x=30 \end{gathered}[/tex]2. Now you need to solve for "x":
[tex]\begin{gathered} x=\frac{30}{10} \\ \\ x=3 \end{gathered}[/tex]3. Substitute the value of "x" into one of the original equations:
[tex]\begin{gathered} x+4y=19 \\ (3)+4y=19 \end{gathered}[/tex]4. Solve for "y":
[tex]\begin{gathered} 3+4y=19 \\ 4y=19-3 \\ 4y=16 \\ \\ y=\frac{16}{4} \\ \\ y=4 \end{gathered}[/tex]Therefore, you can write the solution in this form:
[tex](3,4)[/tex]Hence, the answer is: Option a.