Question

let g(x) = 3x+2 and f(x) = (x-2) /3. Find the value.g(f(2))a) 1b) 0c) 2d) 1/3

Answer 1

Answer:

Given that,

g(x)=3x+2

and f(x)=(x-2)/3

To find,

$g(f(2))$

we get that,

$f(2)=\frac{2-2}{3}$$=0$

Substituting this we get,

$g(f(2))=g(0)$$g(0)=3(0)+2$$g(0)=2$

Hence, we get

$g(f(2))=2$

Answer is: option (c): 2