a.
The work done by a constant force along a rectilinear motion when the force and the displacement vector are not colinear is given by:
[tex]W=F\cos\theta\cdot d[/tex]where F is the magnitude of the force, theta is the angle between them and d is the distance.
The problen gives the following data:
The magnitude of the force 750 N.
The angle between the force and the displacement which is 25°
The distance, 26 m.
Plugging this in the formula we have:
[tex]\begin{gathered} W=\left(750\right)\left(\cos25\right)\left(26\right) \\ W=17673 \end{gathered}[/tex]Therefore the work done is 17673 J.
b)
The power is given by:
[tex]P=\frac{W}{t}[/tex]the problem states that the time it takes is 6 s. Then:
[tex]\begin{gathered} P=\frac{17673}{6} \\ P=2945.5 \end{gathered}[/tex]Therefore the power is 2945.5 W
