We know that the mechanical energy has to be conserved, this means that in an isoleted system we have that:
[tex]K+U=0[/tex]where K is the kinetic energy and U is the potential energy. Since we are in space the potential energy is zero. Then we have that:
[tex]K=0[/tex]Now, remember that the kinetic energy is equal to:
[tex]\frac{1}{2}mv^2[/tex]In this case we have that the conservation of energy means:
[tex]\frac{1}{2}m_av^2_a=\frac{1}{2}m_bv^2_b[/tex]Then:
[tex]\begin{gathered} \frac{1}{2}(80)v^2_a=\frac{1}{2}(5)(5)^2 \\ v_a=\sqrt[]{\frac{5^3}{80}} \\ v_a=1.25 \end{gathered}[/tex]Therefore the velocity of the astronaut is 1.25 m/s