multiply both sides of the inequality by 3
[tex]\begin{gathered} 3\cdot(-\frac{2}{3}x+7)<15\cdot3 \\ -2x+21<45 \end{gathered}[/tex]bring all constants to the right of the inequality
[tex]\begin{gathered} -2x<45-21 \\ -2x<24 \end{gathered}[/tex]divide by -2 both sides of the inequality and invert the sign
[tex]\begin{gathered} x>\frac{24}{-2} \\ x>-12 \end{gathered}[/tex]