Question

Calculate the percent yield of a reaction that had a theoretical yield of 3.76g and an actual yield of 1.45g of titanium (ll) oxide. Round your answer to the correctnumber of sig figs.

Answer 1

The question requires us to calculate the percent yield of a reaction, given its theoretical yield (3.76g) and actual yield (1.45g).

The percent yield of a reaction can be calculated by dividing the actual amount of product obtained - actual yield - by the amount of product that was expected - theoretical yield, and then multiplying this value by 100%:

$\%yield=\frac{actual\text{ yield (g)}}{\text{theoretical yield (g)}}\times100\%$

Thus, considering the values provided by the question, we can calculate the percent yield of the reaction as it follows:

$\%yield=\frac{1.45g}{3.76g}\times100\%=38.6\%$

(note that the values provided by the question present 3 significant figures, thus our answer must have the same amount of significant figures).

Therefore, the percent yield of the reaction is 38.6%.