Given data:
The lenght of one leg is a=8√5.
As, two angle are 45 degrees, 45 degrees, and third one is 90 degrees,
So, it is an isoceles triangle.
The length of other leg is also b=a=8√5.
The expression for hypotenuse is,
[tex]h=\sqrt[]{a^2+b^2}[/tex]
Substitute the given values.
[tex]\begin{gathered} h=\sqrt[\square]{(8\surd5)^2+(8\surd5)^2} \\ =\sqrt[]{320+320} \\ =\sqrt[]{640} \\ =8\sqrt[]{10} \end{gathered}[/tex]
Thus, the other leg is 8√5, and hypotenuse is 8√10.
