Solution:
Given:
[tex]\begin{gathered} P=\text{ \$500} \\ r=7\text{ \%}=\frac{7}{100}=0.07 \\ t=3 \\ n=365...................compounded\text{ daily} \end{gathered}[/tex]Assuming 365days make a year;
Using the compound interest formula,
[tex]\begin{gathered} A=P(1+\frac{r}{n})^{nt} \\ \\ Substituting\text{ the values into the formula:} \\ A=500(1+\frac{0.07}{365})^{365\times3} \\ A=500(1+\frac{0.07}{365})^{1095} \\ A=\text{ \$}616.83 \end{gathered}[/tex]Therefore, after 3years, the investment results in $616.83