practice help!What is the equation of g in terms of f?A. g(x) = f(x)B. g(x) = -f(x)C. g(x) = f(-x)D. g(x) = -f(-x)

To answer this question, we can proceed as follows:
1. We can find the equation for the quadratic function, f(x) (solid line). To do this, we can use the vertex form of quadratic functions as follows:
[tex]f(x)=a(x-h)^2+k[/tex]Where (h, k) is the vertex of the parabola. From the graph, we have that the vertex is (1, -4). We can also see that the y-intercept of this quadratic function is (0, -3). Then with this information, we can find the equation of the function as follows:
[tex]f(x)=a(x-1)^2+(-4)\Rightarrow f(x)=a(x-1)^2-4[/tex]Now, to find the value of as follows:
1. f(0) = -3
[tex]-3=a(0-1)^2-4\Rightarrow-3=a(-1)^2-4\Rightarrow-3=a(1)-4[/tex]Then, we have:
[tex]-3=a-4\Rightarrow-3+4=a-4+4\Rightarrow1=a\Rightarrow a=1[/tex]Then, the equation of the function is:
[tex]f(x)=1(x-1)^2-4\Rightarrow f(x)=(x-1)^2-4[/tex]Now, to find the other function in terms of f(x), we can see that the function, g(x), is the result of reflecting f(x) in the y-axis, f(-x), and then reflecting the resulting function in the x-axis, -f(-x), as follows:
We have that the two functions are:
[tex]f(x)=(x-1)^2-4[/tex][tex]g(x)=-f(-x)\Rightarrow g(x)=-((-x-1)^2-4)[/tex][tex]g(x)=-(-x-1)^2+4[/tex]If we graph both functions, we have:
Therefore, the equation of g in terms of the function f is:
[tex]g(x)=-f(-x)[/tex][Option D.]