Question

How many possible values are there for x in the equation?X2 = 36/81

Answer 1

It is given that

$\begin{gathered} x^2=\frac{36}{81} \\ x=\sqrt[]{\frac{36}{81}} \\ x=\pm\frac{6}{9} \end{gathered}$

So there are two possible values of x .

Hence the correct option is b) two values