Use the next trigonometric ratio for angle 60º in a right triangle:
[tex]\cos 60º=\frac{\text{adjacent leg}}{hypotenuse}=\frac{WX}{YX}[/tex]
Use the given data to solve WX:
[tex]\begin{gathered} \cos 60º=\frac{WX}{6\sqrt[]{3}} \\ \\ WX=6\sqrt[]{3}\times\cos 60 \\ \\ WX=6\sqrt[]{3}\times\frac{1}{2} \\ \\ WX=\frac{6\sqrt[]{3}}{2} \\ \\ WX=3\sqrt[]{3} \end{gathered}[/tex]Then, WX is:[tex]WX=3\sqrt[]{3}[/tex]
