Answer:
Explanation:
a) From the question, we have it that y joint varies as m an n then inversely with the square of d
Let us have k as the variation constant
We have this as:
[tex]\begin{gathered} y\text{ }\alpha\text{ }\frac{mn}{d^2} \\ \\ y\text{ = k}\cdot\frac{mn}{d^2} \end{gathered}[/tex]
b) We want to find the variation constant value
To get this, we use the values supplied in the question
[tex]\begin{gathered} 12\text{ = k}\times\frac{3\times8}{2^2} \\ k\text{ = }\frac{12\times4}{24} \\ k\text{ = 2} \end{gathered}[/tex]
c) We want to find the value of y given the second condition set
mathematically, we have that as:
[tex]y\text{ = }\frac{2\times\text{ - 3}\times18}{3^2}\text{ = -12}[/tex]
