Question

Based on the information below, what are the values of x and y of the solution to the system of equacreate the information?|A|=| 29X=-17/12- 1/2,4--1/114 |, |Ax| =-3X =x = 4, y = 12x = 12, y = 4Previous Activity54|₁|A₂| =0 -30Next Act

Answer 1

Solution.

Given

$|A|=-3(\frac{1}{2})-9(\frac{1}{4})=-\frac{15}{4}$$|A_x|=5(-3)-\frac{1}{4}(0)=-15$$\begin{gathered} |A_y|=\frac{1}{2}(0)-5(9)=-45 \\ \end{gathered}$$\begin{gathered} x=\frac{|A_x|}{|A|}=\frac{-15}{\frac{-15}{4}} \\ x=4 \\ y=\frac{|A_y|}{|A|}=\frac{-45}{\frac{-15}{4}} \\ y=12 \end{gathered}$

Thus, x = 4, y=12