In order to find the energy stored by the car, let's use the formula below:
[tex]E=Q\cdot V[/tex]Where E is the electrical energy, Q is the charge and V is the potential difference (voltage).
So, for Q = 15.4 C and V = 9.16 * 10^8 V, we have:
[tex]\begin{gathered} E=15.4\cdot9.16\cdot10^8 \\ E=141.064\cdot10^8\text{ J} \end{gathered}[/tex]Now, converting this energy into kinetic energy, we have:
[tex]\begin{gathered} E_k=\frac{mv^2}{2} \\ 141.064\cdot10^8=\frac{1780\cdot v^2}{2} \\ 141.064\cdot10^8=890v^2^{} \\ v^2=\frac{141.064}{890}\cdot10^8 \\ v=0.398119\cdot10^4 \\ v=3981.19\text{ m/s} \end{gathered}[/tex]Therefore, putting the answer with 3 significant digits, the velocity of the car would be 3980 m/s.