Question

A rectangular patio has a length of 12 12feet and an area of 103 18square feet. What is the width of the patio?

Answer 1

Given a rectangle with length l and width w, then

$\text{ the area of the rectangle = }lw$

In this case,

$\text{ the area of the rectangle = }103\frac{1}{8}ft^2=\frac{825}{8}ft^2$

and

$l=12\frac{1}{2}ft=\frac{25}{2}ft$

Therefore, we have

$\frac{825}{8}=\frac{25}{2}\times w$

this implies that

$\begin{gathered} \frac{25w}{2}=\frac{825}{8} \\ \text{Cross}-\text{ mulitplying, we have} \\ 25w\times8=2\times825 \\ \text{this implies that} \\ 200w=2\times825 \end{gathered}$$w=\frac{2\times825}{200}=\frac{825}{100}=8\frac{25}{100}=8\frac{1}{4}ft$