Question

if sin x =-2/3 and tan =0, find cos x and cot x. draw a diagram to show where angle x is found in a coordinate plane. no decinal answer

Answer 1

Find the adjacent side

3^2 = 2^2 + b^2

b^2 = 9 - 4

b^2 = 5

b = squared root of 5

$\begin{gathered} \cos \text{ x = }\frac{\sqrt[]{5}}{3} \\ \cot \text{ x = }\frac{\sqrt[]{5}}{2} \end{gathered}$