The given figure can be divided into a square, an isosceles trapezoid, and a semi-circle. Let's find the area of each part
[tex]\begin{gathered} A_{\text{square}}=13^2=169in^2 \\ A_{\text{trapezoid}}=\frac{(B+b)\cdot h}{2}=\frac{(30+13)\cdot20}{2}=430in^2 \\ A_{circle}=\frac{\pi(r)^2}{2}\approx\frac{3.14\cdot15^2}{2}\approx353.25in^2 \end{gathered}[/tex]At last, we add all three areas
[tex]A=169+430+353.25=952.3in^2[/tex]
